Q1. THE PERIMETER OF AN ISOSCELES TRIANGLE IS 36CM AND HEIGHT IS 12CM, THEN FIND ITS AREA. SOL:- AB = AC, BC = BD + DC AB+ AC + BC =36 CM . AB +AB +BC = 36 CM 2AB + 2BD = 36CM. 2( AB + BD) = 36 CM. AB + BD = 18 CM .......................1 NOW PYTHAGORAS'S THEOREM. AB^2 = AD^2 + BD^2 AB^2 - BD^2 = AD^2. ( AB+BD )( AB -BD) = 12^2 18 CM (AB - BD) = 144 AB- BD = 144/18 AB - BD = 8 CM ................................2. FROM EQUATION 1 & 2 AB + BD = 18 CM AB - BD = 8 CM .................................................................