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ABOUT NEW TIMES COACHING CENTRE

    ABOUT NEW TIMES COACHING CENTRE  We are committed to take education to every single door, making it a superb blend of knowledge and job specific. Our mission is to create ethical and intellectual personnel through qualitative education. Today, New TIMES Coaching Centre is located at Anisabad, Patna, Bihar. And, we are looking forward to spread our efficiency at every nook and corner of India. We are the player with diverse courses, teaching methodology, efficient faculty team and effective management staff. Choose to contact or reach us for an assured advanced career. Organizing studies properly for pupils is essential in case they dream of doing something great in the future. Also the scores obtained in this class help pupils to choose their stream. Since school children give exams for the first time in the board and the way they understand all the concepts make students capable of solving different problems related to routine life. Also, it will prove beneficial in further studie

REAL NUMBER FOR CLASS 10.

1. EUCLID'S DIVISION LEMMA:--Let a and b be any two positive integers.  Then ,there exist unique integers q  and r such that                      a = bq +  r , o ≤ r <  b .          Dividend (a) = divisor (b)  × quotient (q)  + remainder (r). 2. Algorithm:- an algorithm is a series of well defined steps which gives a procedure for solving a type of problem . 3. Lemma:-  A Lemma is a proven statement used for proving another statement . 4. EUCLID'S DIVISION ALGORITHM:-  Euclid's  division algorithm is a technique to compute the highest common factor (H.C.F. )of two given positive integers. Q1. A number when  divided by 73 gives  34 as quotient and 23 as remainder . Find the number . SOLUTION:-  Dividend = (divisor × quotient)  + remainder .                                           =(73 × 34 ) + 23                                           =2482  + 23                                           =2505.    Hence ,the required number is 2505.                             REAL N

TRIGONOMETRY PART 2

Q1. In a triangle ABC, right angled at B, in which AB = a and BC = a .Find the value of SecA . Q2. CosA = 5/13 Find the value of    SinA --  CotA.     [B]        CotA  +       1                                                                               2 TanA                                         CosA. Q3. If  SinA  +  CosecA  = 2 ,  Find  the  value  of  sin 2 A +  Cosec 2 A . Q4. If 4 Sinθ  = 3 cosθ .  find the value of  {a}    sinθ .       {b}  Cosθ.      {c} tanθ . Q5. In a ∆ABC , Right angled  at  B ,   It  is given that    AB  = 5 CM and  BC + AC  = 25 CM        Find the values of   1. SinA     2. SinC        3.CosA       4. CosC       5.TanA       6.TanC   Q6. In a  ∆ABC , Right angled at B ,It  is given that    AB  =7 CM and (AC—BC) = 1CM   Find the value of  1. SinA     2. SinC     3.CosA       4. CosC      5.TanA       6.TanB Q7.  Express the trigonometric ratios    sinA   ,CosA   , secA    and     tanA      In  terms of    cotA. Q8.  Prove the following identities :-